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已知tan2α=2tan2β+1 求证:sin2 β=2sin2α-1 谁能用切割化玄做出这个问题啊?
人气:361 ℃ 时间:2020-02-05 13:32:40
解答
tan^2α=2tan^2β+1sin^2α/cos^2α=2sin^2β/cos^2β+1sin^2α/cos^2α=(2sin^2β+cos^2β)/cos^2βsin^2α/cos^2α=(sin^2β+1)/cos^2βsin^2α/(1-sin^2α)=(sin^2β+1)/(1-sin^2β)sin^2α-sin^2α*sin^2β=sin^...
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