已知（x+2）^2+|x+y+5|=0,求3x^2y-[2x^2y-(2xy-x^2y)-4x^2]-xy
人气：234 ℃ 时间：2019-08-19 13:51:53
解答
（x+2）^2+|x+y+5|=0,
x+2=0,x+y+5=0
x=-2,y=-3
3(x^2)y-2(x^2)y+2xy-(x^2)y+4x^2-xy
=4x^2+xy
=4*(-2)^2+(-2)*(-3)
=16+6
=22
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