(x/3)*3m = (1+20%)[(16/3)*m+(21/4)*2m]
（1）当m =0时,x为任何实数.
（2）当m ≠0时,等式两侧都除以m得
x=(1+20%)[(16/3)+(21/4)*2] =6/5*(16/3+21/2)=6/5*(95/6)=19