一个英语的物理题,牛人请进
昨天做题遇到一个物理题目,虽然不难但是难以理解,做不下来啊》》
望高手们予以回答：
An object is launched from the ground with an initial velocity and angle such that the maximum high height achieved is equal to the total range of the projectile.The tangent of the launch angle is equal:
A:1
B:2
C:3
D:4
E:5
At a launch angle of 45',the range of a launched prijectile is given by:
A:(Vi)^2/g
B:2(Vi)^2/g
C:(Vi)^2/2g
D:根号下[(Vi)^2/2g]
E:2Vi/g
欢迎英语牛人进行翻译,
最近积分用完了,我去储储.
正确,我看看有没更详细的.