椭圆x²/5+y²/m=1与直线y=kx+1恒有公共点则(5k²+m)x²+10kx+5-5m=0恒有实数根∵m>0且m≠5∴5k²+m≠0∴△=100K²-20(1-m)(5k²+m)≥0∴k²+(m-1)/5≥0恒成立∴m的取值范围为[1,5)...