x²-5x-2000=0x²-5x=2000于是[(x-2)³-(x-1)²+1]/(x-2) =[(x-2)³-(x²-2x+1)+1]/(x-2) =[(x-2)³-x²+2x]/(x-2) =[(x-2)³-x(x-2)]/(x-2) =(x-2)[(x-2)²-x]/(x-2) =(x-...