求y=sinx*sin(x+60)的最大值
人气:157 ℃ 时间:2020-03-31 17:46:31
解答
y=sinx(sinxcos60+cosxsin60)=1/2(sinx)^2+√3/2*sinxcosxcos2x=1-2(sinx)^2,所以(sinx)^2=(1-cos2x)/2sin2x=2sinxcosx,sinxcosx=1/2*sin2x所以y=√3/4*sin2x-1/4*cos2x+1/4=√[(√3/4)^2+(1/4)^2]*sin(2x-a)+1/4=1/...
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