a*a+4a+1=0,且a*a*a*a+m*a*a+1/2a*a*a+ma*a+2a=3求m的值_数学解答

a*a+4a+1=0,且a*a*a*a+m*a*a+1/2a*a*a+ma*a+2a=3求m的值

人气：340 ℃　时间：2020-04-11 04:21:51

解答

because(以下简写b): a*a+4a+1=0So,(a^2+2a+1)+2a=0 (a+1)^2+2a=0 [(a+1)^2+2(a+1)+1]-3=0 [(a+1)+1]^2-3=0 (a+2)^2=3 a+2=+/-根号3 a=+/-(根号3) -2代入后面...