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4x²-6x-(y-2)(y+1)=0分解因式
人气:459 ℃ 时间:2020-04-16 06:04:33
解答
4x²-6x-(y-2)(y+1)=04x²-6x-(y²+y-2y-2)=04x²-6x-y²+y+2=04(x²-3/2x)-(y²-y)+2=04(x²-3/2x+9/16)-9/4-(y²-y+1/4)+1/4+2=04(x-3/4)²-(y-1/2)²=0[2(x-3/4)+(y...
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