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sin2a-2cos^2 a/sin(a-π/4)=?化简
人气:342 ℃ 时间:2020-02-03 02:27:14
解答
(sin2a-2cos^2 a)/sin(a-π/4)
=(2sinacosa-2cos²a)/(sinacosπ/4-cosasinπ/4)
=2cosa(sina-cosa)/[√2/2·(sina-cosa)]
=2√2·cosa
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