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计算x∧2-(y-z)∧2/(x+y)∧2-z∧2分式约分,
人气:498 ℃ 时间:2020-04-10 23:32:49
解答
=(x+y-z)(x-y+z)/(x+y+z)((x+y-z)
=(x-y+z)/(x+y+z)那x∧2-(y-z)∧2/(x-y)∧2-z∧2该怎么算呢?=(x+y-z)(x-y+z)/(x-y+z)(x-y-z)=(x+y-z)/(x-y-z)
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