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lim(x→0)lncos2x/lncos3x
用等价无穷小量求
人气:248 ℃ 时间:2020-05-30 02:11:32
解答
lim(x→0)lncos2x/lncos3x
=lim(x→0)ln(1+cos2x-1)/ln(1+cos3x-1)
=lim(x→0) (cos2x-1)(cos3x-1)
=lim(x→0) (2x)^2/(3x)^2
=4/9
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