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lim(x→∞)[(x^2-2x+1)/(x+1)直接化简即可:
lim(x→∞)[(x^2-2x+1)/(x+1)]
=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]
=lim(x→∞)[x-3+4/(x+1)]
我不知道下面这一步是怎么得来的:
=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]
=lim(x→∞)[x-3+4/(x+1)]
x^2-3x去哪里了呢?
人气:287 ℃ 时间:2020-06-06 10:44:47
解答
lim(x→∞)[(x²+x-3x-3+4)/(x+1)]
=lim(x→∞){[(x²+x)-3(x+1)+4]/(x+1)}
=lim(x→∞)[(x²+x)/(x+1)-3(x+1)/(x+1)+4/(x+1)]
=lim(x→∞)[x-3+4/(x+1)]
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