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数学
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(2x^2y-2xy^2)-[(-3x^2y^2+3x^2y)+(3x^2y^2-3xy^2)]其中x=-1,y=2
人气:492 ℃ 时间:2019-08-18 15:17:16
解答
(2x^2y-2xy^2)-[(-3x^2y^2+3x^2y)+(3x^2y^2-3xy^2)]
=-x^2y+xy^2,其中x=-1,y=2,所以=-2-4=-6
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