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(2x^2y-2xy^2)-[(-3x^2y^2)+(3x^2y^2-3xy^2)]其中x=-1,y=2
人气:214 ℃ 时间:2019-08-19 01:33:42
解答
原式=2x^2y-2xy^2-(-3x^2y^2+3x^2y^2-3xy^2)
=2x^2y-2xy^2-(-3xy^2)
=2x^2y-2xy^2+3xy^2
=2x^2y+xy^2
=2×1×2+(-1)×4
=4-4
=0
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