y=-2x^2+(m+3)x+(1-m)x1+x2=(m+3)/2x1x2=(m-1)/2所以(x1-x2)^2=(x1+x2)^2-4x1x2=(m+3)^2/4-2(m-1)=m^2/4-m/2+17/4=(1/4)(m-1)^2+4所以m=1,(x1-x2)^2最小=4所以距离|x1-x2|最小=根号4=2