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导数运算习题 y=(x+1)^2(x-1)
人气:249 ℃ 时间:2020-05-31 09:48:35
解答
y'=(x^2+2x+1)'*(x-1)+(x^2+2x+1)*(x-1)'
=(2x+2)*(x-1)+(x^2+2x+1)*1
=(2x^2-2)+(x^2+2x+1)
=3x^2+2x-1
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