复数内可以!ax²+bx+cax²+bx+c=a(x-x1)(x-x2)x1=[-b+√(b²-4ac)]/2ax2=[-b-√(b²-4ac)]/2a5x²-3x+17a=5,b=-3,c=17x1=[-b+√(b²-4ac)]/2a=[3+i√331]/10=0.3+i1.82x1=[-b+√(b²+4a...