> 数学 >
化简代数式{(a-b)/(a+2b)}/{(a²-b²)/(a²+4ab+4b²)}-1
人气:336 ℃ 时间:2019-11-25 20:09:38
解答
{(a-b)/(a+2b)}/{(a²-b²)/(a²+4ab+4b²)}-1={(a-b)/(a+2b)}/{(a+b)(a-b)/(a+2b)²}-1=(a-b)(a+2b)²/(a+b)(a-b)(a+2b)²-1=(a+2b)/(a+b)-1=b/(a+b)...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版