三角形ABC,AB=AC,
人气:198 ℃ 时间:2019-12-09 19:17:27
解答
∵∠AEC=∠AEC(公共角)、∠BDE=∠CAE=90度∴∠DBE=∠ACE∴△BDE∽△AEC∴BD/AC=DE/AE设AB=AC=2,则BC=2√2又∵∠DBC=60度∴∠DCB=30度∴BD=√2∴BD/AC=DE/AE=(√2)/2又S△BDE=1/2×BD×DE,S△CAE=1/2...
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