化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot_数学解答

化简:cos(90°+α)·csc(370°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α）
·是乘号.最后答案是1.求过程.
= =。啊sorry……是270°……我看错了。呃。
【cos(90°+α)·csc(270°+α)·tan(180°-α)】/【sec(360°-α)·sin(180°+α)·cot(90°-α）】

人气：495 ℃　时间：2020-03-31 07:52:10

解答

还是原来的题目错了,现在对了

cos(90°+α)·csc(270°+α)·tan(180°-α)/sec(360°-α)·sin(180°+α)·cot(90°-α）
=sin(-a)*(-1/cosa) * tan(-a) /(1/cos(a))sin(-a)tan(a)
=1
终于和答案对上了
采纳我吧