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数学
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27^(2/3)-2^(log以2为底的3)×log以2为底的1/8+lg4+2lg5=?
人气:332 ℃ 时间:2020-02-03 15:11:09
解答
27^(2/3)-2^(log以2为底的3)×log以2为底的1/8+lg4+2lg5=
=3^2-3×log以2为底的(2^-3)+lg4+lg5^2
=9-3×(-3)+lg(4×25)
=9+9+lg100
=18+2
=20
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