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求y=arccos(x+1/x-1)导数
人气:189 ℃ 时间:2020-04-16 20:46:13
解答
y=arccos(x+1)/(x-1)
y'=-1/√[1-((x+1)/(x-1))^2] * ((x+1)/(x-1))'
y'=2/√[1-((x+1)/(x-1))^2] * (1/(x-1)^2)
因为:1-((x+1)/(x-1))^2>0
(x-1)^2-(x+1)^2>0,即:-4x>0,x
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