(x+2)(x+2-3)=0,
(x+2)(x-1)=0.
x+2=0或x-1=0.
∴x1=-2,x2=1.
(2)原方程可变形为
(3x+2-2x)(3x+2+2x)=0,
即(x+2)(5x+2)=0.
x+2=0或5x+2=0.
∴x1=-2,x2=-
2 |
5 |
(3)原方程可变形为
(2x-1)(5+x+3)=0,
即(2x-1)(x+8)=0
2x-1=0或x+5=0
∴x1=
1 |
2 |
(4)原方程可变形为
2(x-3)2-x(x-3)=0,
(x-3)(2x-6-x)=0,
(x-3)(x-6)=0.
x-3=0或x-6=0.
∴x1=3,x2=6.