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数学
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分解因式(x+y)(x+y+2xy)+x^2y^2-1
人气:436 ℃ 时间:2020-05-13 00:28:50
解答
原式=(x+y)^2+2xy(x+y)+(xy)^2-1
=(x+y+xy)^2-1
=(x+y+xy-1)(x+y+xy+1)
=(xy+x+y-1)(x+1)(y+1)
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