将方程展开整理得
√2x²-√2-x²+2x-1=0
（√2-1）x²+2x-（√2+1）=0
√2-1 √2+1
1 -1
∴[(√2-1)x+(√2+1)]﹙x-1﹚=0
∴x1=1,x2=﹙√2+1﹚／(√2-1)=-3-2√2