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1/(1*3)+1/(3*5)+1/(5*7)+1/(7*9)...1/(199*201)=?
人气:148 ℃ 时间:2020-02-03 02:28:05
解答
1/(1*3)+1/(3*5)+1/(5*7)+1/(7*9)...1/(199*201)=1/2(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9...+1/199-1/201)=100/201怎么做的,说的明白就给你分我不需要分,谢谢1/(n×(n+2))=1/2(1/n-1/(n+2))
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