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y=sin((1/2)x+(π/3))的单调递增区间
人气:116 ℃ 时间:2020-05-22 07:16:45
解答
y=-sin(x/2-π/3)所以y增区间即sin(x/2-π/3)的减区间sinx的减区间是(2kπ+π/2,2kπ+3π/2)2kπ+π/2<x/2-π/3<2kπ+3π/22kπ+5π/6<x/2<2kπ+11π/64kπ+5π/3<x<4kπ+11π/3k=-1,则-7π...
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