函数f(x)=4x²-mx+5在区间[-2,正无穷)内是增函数,则f(1)的取值范围是____?
人气:166 ℃ 时间:2019-09-22 09:10:05
解答
二次函数,开口向上,在对称轴右边是递增的,对称轴为x=m/8,
所以由在区间[-2,正无穷)内是增函数,得:区间[-2,正无穷)在对称轴x=m/8的右边;
即m/8≦-2,得m≦-16;
所以:f(1)=9-m≧25
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