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sinx+tanx/1+cosx= 化简吧
(sinx+tanx)/(1+cosx)
人气:290 ℃ 时间:2020-05-23 05:26:23
解答
sinx+tanx/1+cosx
=(sinx+sinx/cosx)/(1+cosx)
=(sinxcosx+sinx)/[cosx(1+cosx)]
=sinx(cosx+1)/[cosx(1+cosx)]
=sinx/cosx
=tanx
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