已知m2+n2=5,求代数式(2m2+3n2-mn)-(3m2+4n2-mn)的值.
人气:107 ℃ 时间:2019-08-21 01:14:18
解答
(2m2+3n2-mn)-(3m2+4n2-mn)
=2m2+3n2-mn)-3m2-4n2+mn
=-m2-n2
=-(m2+n2);
把m2+n2=5代入上式,得
上式=-5,即代数式(2m2+3n2-mn)-(3m2+4n2-mn)的值是-5.
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