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[4a^nb^n-1﹙﹣6a^3b^4)+(﹣3a^nb^n)(﹣2ab)^3]÷3ab=
人气:110 ℃ 时间:2019-11-09 10:00:04
解答
原式=[4a^nb^(n-1)×(-6a³b^4)+(-3a^nb^n)×(-2)³×a³×b³]÷3ab=[4×(-6)×a^n×a³×b^(n-1)×b^4+(-3)×(-8)×a^n×a³×b^n×b³]÷3ab=[-24a^(n+3)×b^(n+3)+24a^(n+3)×b^(n+...
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