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解分式方程:1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
人气:425 ℃ 时间:2020-03-27 03:36:30
解答
1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
1/(x-3)-1/(x-4)=1/(x-6)-1/(x-7)
(x-4-x+3)/(x-3)(x-4)=(x-7-x+6)/(x-6)(x-7)
-1/(x-3)(x-4)=-1/(x-6)(x-7)
(x-6)(x-7)=(x-3)(x-4)
x²-13x+42=x²-7x+12
-6x=-30
x=5
检验:x=5是方程的根
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