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p(p+q)2-(p-q)(p2+pq+q2)
人气:464 ℃ 时间:2020-02-05 19:10:32
解答
p(p+q)2-(p-q)(p2+pq+q2)= p(p+q)2-(p-q) [ (p2+2pq+q2) - pq ] = p(p+q)2-(p-q) [ (p+q)2 - pq ] = p(p+q)2- (p-q) ( p+q)2 + pq (p-q)= ( p+q)2 ( p -p+q ) + pq (p-q)= q ( p+q)2 + pq (p-q) = q ( p² +q...
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