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数学
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化简:sin^2a*tana+cos^2a/tana+2sina*cosa
人气:122 ℃ 时间:2020-03-18 01:07:33
解答
sin^2a*tana+cos^2a/tana+2sina*cosa
=(1-cos^2a)*tana+(1-sin^2a)/tana+2sina*cosa
=tana-sina*cosa+1/tana-sina*cosa+2sina*cosa
=tana+1/tana
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