根号sin^α-sin^4α（π/2〈α〈π）化简根号sin平方α-sin4次方α（π/2〈α〈π）化简··········_数学解答

根号sin^α-sin^4α（π/2〈α〈π）化简
根号sin平方α-sin4次方α（π/2〈α〈π）化简··········

人气：337 ℃　时间：2020-01-26 04:12:05

解答

这个sin^2α-sin^4α?
sin^2α-sin^4α
=sin²α(1-sin²α)
=sin²αcos²α
=1/4(2sinαcosα)²
=1/4sin²2α