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(x+2/x^2-2x-x-1/x^2-4x+4)/x-4/x ,x=2-根号5.最后等于多少?
人气:467 ℃ 时间:2019-08-19 19:54:35
解答
(x+2/x^2-2x-x-1/x^2-4x+4)/x-4/x
=[(x+2)/x(x-2)-(x-1)/(x-2)²]/(x-4)/x
=[(x²-4-x²+x)/x(x-2)²]×x/(x-4)
=[(x-4)/x(x-2)²]*[x/(x-4)]
=1/(x-2)²
=1/(2-√5-2)²
=1/5
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