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若x=π/16,y=3π/16 ,则(1+tanx)(1+tany)=?
人气:462 ℃ 时间:2020-05-23 21:26:45
解答
x+y=π=4 所以tan(x+y)=tanπ/4=1=(tanx+tany)/(1-tanx*tany)
推出tanx+tany=1-tanxtany
(1+tanx)(1+tany)=1+tanxtany+tanx+tany=1+1-tanxtany+tanxtany=2
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