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计算:√3sin(-20/3∏)-cos13/4π×tan(-37/4π)
人气:262 ℃ 时间:2020-06-29 21:03:34
解答
√3sin(-20/3π)-cos13/4π×tan(-37/4π)
=√3sin(-7π+1/3π)-cos(3π+1/4π)×tan(-9π-1/4π)
=-√3sin(1/3π)+cos(1/4π)×tan(-1/4π)
=-√3×(√3/2)+√2/2×(-1)
=-(3+√2)/2
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