>
数学
>
计算:√3sin(-20/3∏)-cos13/4π×tan(-37/4π)
人气:262 ℃ 时间:2020-06-29 21:03:34
解答
√3sin(-20/3π)-cos13/4π×tan(-37/4π)
=√3sin(-7π+1/3π)-cos(3π+1/4π)×tan(-9π-1/4π)
=-√3sin(1/3π)+cos(1/4π)×tan(-1/4π)
=-√3×(√3/2)+√2/2×(-1)
=-(3+√2)/2
推荐
计算:cos13π/4+tan(-11π/6)=?
根号3sin(-1200°)tan11π/6-cos585°tan(-37π/4)
已知tanα=-3/4,计算:2sin²а+3sinаcosа-cos²а
已知tanα=3,计算:(1)4sinα-2cosα5cosα+3sinα;(2)sinαcosα;(3)(sinα+cosα)2.
已知tanα=-3/4,则3sinα+2cosαsinα−4cosα=_.
改错:Noddles are popular in China.
抛物线y=a(x+h)²与直线y=ax+b相交于点(-1,1),且抛物线的对称轴为x=-2.求抛物线y=a(x+h)²和直线y=ax+b的解析式
He always talks的同义句
猜你喜欢
一个圆有多少条切线?
1、火车速度比汽车快55%,汽车速度就比火车慢55%.( ) 2、乙是甲的60%,则甲比乙多40%.( )
X(X-2)-3X=0 因式分解法
We()(have)a school Sports Day last week.All the students()(do)a good job.We()(are)in second place.We()(win)5 gold medals
1 2 3 4 5=6 7 8 9怎么填运算符号
mum likes to go to the shops,it's sunday today i help my mother go shopping my brother is with 翻译
保护水节约水关注水话题作文
n趋于无穷大,lim ( n次方根(1+|x|^3n) ) 等于什么?它说等于|x|^3 * lim( ( 1+1/(|x|^3))^(1/n) ) ,为啥
© 2026 79432.Com All Rights Reserved.
电脑版
|
手机版