高一三角函数一道化简问题
[siny+sinxcos(x+y)]/[cosy-sinxsin〔x+y〕]
化简
人气:208 ℃ 时间:2020-05-24 01:11:11
解答
siny+sinxcos(x+y)=siny+sinx(cosxcosy-sinxsiny)=siny+sinxcosxcosy-siny*(sinx)^2=siny[1-(sinx)^2]+sinxcosxcosy=sinycosx^2+sinxcosxcosy=cosx(sinycosx+sinxcosy)=cosxsin(x+y)同理,计算可以得到cosy-sinxsin(x...
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