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sin^2b=tan^2b/1+tan^2b
人气:109 ℃ 时间:2020-04-19 21:30:46
解答
证明:
tan²b/(1+tan²b)
=(sin²b/cos²b)/(1+sin²b/cos²b)
=(sin²b/cos²b)/[(cos²b+sin²b)/cos²b]
=(sin²b/cos²b)/(1/cos²b)
=sin²b
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