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sin(π-α)=-2sin(π/2+α),求sinα·cosα
人气:216 ℃ 时间:2020-02-03 04:48:45
解答
化简sin(π-α)=-2sin(π/2+α),得sinα=-2cosα.
再联立(sinα)^2+(cosα)^2=1,求出(cosα)^2=1/5
sinα·cosα=-2(cosα)^2=-2/5
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