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求下列各式的值 1.sin20°cos70°+sin10°sin50° 2.cos八分之五πcos八分之π
人气:133 ℃ 时间:2020-06-25 18:56:24
解答
1.sin20°cos70°+sin10°sin50° =sin20°sin20°+(cos40°-cos60°)/2 =(1-cos40°)/2+(cos40°-cos60°)/2 =(1-cos60°)/2=(1-1/2)/2=1/4.2.cos(5π/8+π/8)=cos5π/8cosπ/8-sin5π/8sinπ/8=-√2/2cos(5π/8...
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