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a/a^2+a+1=1/8,则a^2/a^4+a^2+1=?
人气:239 ℃ 时间:2020-06-15 07:56:01
解答
a/(a^2+a+1)=1/8
1/(a+1/a+1)=1/8
a+1/a+1=8
a+1/a=7
a^2/(a^4+a^2+1)
=1/(a^2+1/a^2+1)
=1/[(a+1/a)^2-1]
=1/(7^2-1)
=1/48
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