已知n为正整数,且x的2n次方为7,求(2x^2n)^3-7(x^2)^2n的值
人气：112 ℃ 时间：2019-09-17 03:31:23
解答
原式=2^3×（x^2n）^3-7（x^2n）^2=8×7^3-7×7^2=（8-1）×7^3=7^4=2401
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