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数学题在线解答1/(x+1)*(x+2)+1/(x+2)*(x+3)+1/(x+3)*(x+4)+.+1/(x+99)*(x+100)
当x=5时,求代数式的值。
人气:284 ℃ 时间:2019-10-17 05:28:30
解答
1/(x+1)*(x+2)+1/(x+2)*(x+3)+1/(x+3)*(x+4)+.+1/(x+99)*(x+100)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+.+1/(x+99)-1/(x+100)=1/(x+1)-1/(x+100)=99/ (x+1)(x+100)x=5时原式=99/(6*105)=11/70
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