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计算:(-4/3a^2b^2)(3/2a^2+ab-3/5b^2)/(4/3a^2b^2)
人气:458 ℃ 时间:2020-01-29 08:07:15
解答
(-4/3a^2b^2)(3/2a^2+ab-3/5b^2)/(4/3a^2b^2)
=[(-4/3a^2b^2)/(4/3a^2b^2)](3/2a^2+ab-3/5b^2)
=-(3/2a^2+ab-3/5b^2)
=-3/2a^2-ab+3/5b^2
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