[(x-y)(y-z)]³-[(y-x)(y-z)]³=[(x-y)(y-z)]³-[-(x-y)(y-z)]³=[(x-y)(y-z)]³+[(x-y)(y-z)]³=2[(x-y)(y-z)]³很高兴为您解答,【数学之美】团队为您答题.请点击下面的【选为满意回答...