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分解因式5(x+y)²+23(x²-y²)-10(x-y)²
人气:325 ℃ 时间:2020-05-14 00:33:28
解答
5(x+y)²+23(x²-y²)-10(x-y)²
=5(x+y)²+23(x+y)(x-y)-10(x-y)²
=[5(x+y)-2(x-y)][(x+y)+5(x-y)]
=(3x+7y)(6x-4y)
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