原式=|[(i*√216)^3*(3/4)]/[(1/2)*i*4/3]|=|i^3*216*√216*(3/4)]/[i*(2/3)]=|(-i*216*6√6)*(3/4)/[i*(2/3)]=|[ -216*6√6*(3/4)]/(2/3)|..=|-27*9*6√6|=|.-11664√6| =11664√6.【这是一道复数运算题,√(-216)=2...